Answer:
Step-by-step explanation:
Problem One (left panel)
<em><u>Question A</u></em>
- The y intercept happens when x = 0
- That being said, the y intercept is 50. It was moving when the timing began.
<em><u>Question B</u></em>
The rate of change = (56 - 52)/(3 - 1) = 4/2 = 2 miles / hour^2 (you have a slight acceleration.
<em><u>Question C</u></em>
- 60 = a + (n-1)d
- 60 = 50 + (n - 1)*2
- 10/2 = (n - 1)*2/2
- 5 = n - 1
- 6 = n
The way I have done it the domain is n from 1 to 6
Question 2 (Right Panel)
<em><u>Question A</u></em>
The equation for the table is f(x) = 3x - 3 which was derived simply by putting all three points into y = ax + b and solving.
- f(0) = ax + b
- -3 = a*0) + b
- b = - 3
- So far what you have is
- f(x) = ax - 3
- f(-1) = a*(-1) - 3 but we know (f(-1)) = -6
- - 6 = a(-1) - 3 add 3 to both sides
- -6 +3 = a(-1) -3 + 3
- -3 = a*(-1) Divide by - 1
- a = 3
- f(x) = 3x - 3 Answer for f(x)
- The slope of f(x) = the coefficient in front of the x
- f(x) has a slope of 3
- g(x) has a slope of 4
<em><u>Part B</u></em>
- f(x) has a y intercept of - 3
- g(x) has a y intercept of -5
- f(x) has the greater y intercept.
- -3 > - 5
According to one source, the answer is "C. Randomly select and replace a donut 72 times. Then, observe how close to 18 times a glazed donut is drawn. "
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Answer:
y = 3x
Step-by-step explanation:
The exact equation for the climb would be y = (x-3)^2 + 9, however, a rough line that represents the climb is y = 3x.
Find the slope between (0, 0) and (3, 9) and we get m = 3. Plug it into y-int form and you get the line.
The area of circle having radius 3cm is 28.27 cm², diameter 5cm is 19.63 cm², radius 8 ft is 201.06 ft², diameter is 113.1 cm², diameter 20 km is 314.16 km², diameter 15 mm is 176.71 mm² and radius 16 yd is 804.25 yd².
Given the radius and diamtere are (a) Radius (r) = 3 cm (b) Diameter (d) = 5 cm (c) Radius (r) = 8 ft. (d) Diameter (d) = 12 cm (f) Diameter (d) = 20 km (g) Diameter (d) = 15 mm (i) Radius (r) = 16 yd.
We will calculate the area of circle by using the formula A=πr² or π(d/2)².
(a) Radius (r)=3cm
The area of circle is
Area=π(3)²
Area =9π
Here, π=3.14, we get
Area =9×3.14
Area=28.27cm²
(b) Diameter (d)=5cm
The area of circle is
Area=π(5/2)²
Area =π(2.5)²
Area=6.25π
Here, π=3.14, we get
Area =6.25×3.14
Area=19.63cm²
(c) Radius (r)=8 ft
The area of circle is
Area=π(8)²
Area =64π
Here, π=3.14, we get
Area =64×3.14
Area=201.06ft²
(d) Diameter (d)=12cm
The area of circle is
Area=π(12/2)²
Area =36π
Here, π=3.14, we get
Area =36×3.14
Area=113.1cm²
(e) Diameter (d)=20km
The area of circle is
Area=π(20/2)²
Area =100π
Here, π=3.14, we get
Area =100×3.14
Area=314.16km²
(f) Diameter (d)=15mm
The area of circle is
Area=π(15/2)²
Area =56.25π
Here, π=3.14, we get
Area =56.25×3.14
Area=176.71mm²
(g) Radius (r)=16yd
The area of circle is
Area=π(16)²
Area =256π
Here, π=3.14, we get
Area =256×3.14
Area=804.25yd²
Hence, the area of circle having radius and diameter is radius 3cm is 28.27 cm², diameter 5cm is 19.63 cm², radius 8 ft is 201.06 ft², diameter is 113.1 cm², diameter 20 km is 314.16 km², diameter 15 mm is 176.71 mm² and radius 16 yd is 804.25 yd².
Learn more about the area of circle from here brainly.com/question/17096708
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