Answer:
Step-by-step explanation:
WITHOUT replacement of first card drawn:
P(a 10 is drawn) = 13/52 = 1/4
P(the next draw is a 10) = 12/52 = 3/13
P(drawing two 10s without replacement of the first draw) = (1/4)(3/13) = 3/52
WITH replacement of first card:
P(two 10s are drawn) = P(first card is a 10)*P(first card is a 10) = (4/13)(4/13) =
16/169
1)t=S/U=2.4/12=0.2
2)t=S/U=8.4/36=0,23
3)0.23-0.2=0.03
Answer:
The person would have to play 2 games for the two bowling alleys to cost the same amount
Step-by-step explanation:
Assume that the number of games that makes the two costs equal is x
∵ A bowling alley charges $2.50 per game plus $4 to rent shoes
∵ The number of games is x
∴ The cost = 2.50x + 4
∵ A second bowling alley charges $4 per game plus $1 to rent shoes
∵ The number of games is x
∴ The cost = 4x + 1
∵ They have the same cost
→ Equate the 2 expressions above
∴ 4x + 1 = 2.50x + 4
→ Subtract 2.50x from both sides
∵ 4x - 2.50x + 1 = 2.50x - 2.50x + 4
∴ 1.50x + 1 = 4
→ Subtract 1 from both sides
∵ 1.50x + 1 - 1 = 4 - 1
∴ 1.50x = 3
→ Divide both sides by 1.50
∴ x = 2
∴ The person would have to play 2 games for the two bowling alleys to
cost the same amount
One way to do this is to notice
Then
We have
and since has a period of ,
and so