P + (-q) - 2 = ? When p = -3 and q = 5
2 answers:
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The coordinates for the pre-image are P(1,3), Q(4,4), R(4,1), and S(1, -1).
The transformation is 4 units left, and 4 units down.
That means we must subtract 4 units to x-coordinates, and subtract 4 units from y-coordinates. So, the image has coordinates P'(-3,-1), Q'(0,0), R'(0, -3), and S'(-3, -5).
The image below shows the image and pre-image.
For this case we have the following expression:
Rewriting the expression we have:
Where,
x: exponent to which we must raise the expression to obtain 7 as a result.
We have then:
The exponent must be equal to 1:
Clearing x we have:
Substituting valres:
Answer:
you must raise the expression to 2
Rewriting the expression we have:
Where,
x: exponent to which we must raise the expression to obtain 7 as a result.
We have then:
The exponent must be equal to 1:
Clearing x we have:
Substituting valres:
Answer:
you must raise the expression to 2