3a- 2b + 8b - 2 + 6a + 3c
3a + 6a -2b +8b + 3c - 2
9a + 6b + 3c - 2
Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
<em>~ an aesthetics lover</em>
Answer:
When we are trying to square a number say x, to x²,then we multiply the number x with number of powers
here since it is x² we multiply x × x
if it is x³,then x × x × x
Answer:
he didnt subtract each equations on both sides
5y-6=4y+1
-4 -4
y -6=1
+6=+6
y=7
Step-by-step explanation:
hope that wrk
Factors are things that you multiply so p is a factor and q-1 is a factor