Answer:
Explanation:
<u>Chemical formulas for every compound:</u>
Potassium vapor =>
Molten soldium chloride =>
Molten Potassium chloride =>
Molten Sodium Metal =>
<u>The reaction will be as follows:</u>
This reaction is usually called displacement reaction in which an element displaces another element of a compund.
Sodium oxide and carbon dioxide
Explanation:
When sodium carbonate decomposes sodium oxide and carbon dioxide is produced:
Na₂CO₃ → Na₂O + CO₂
- This kind of reaction is known as decomposition reaction.
- In a decomposition reaction,
- In this kind of reaction, two or more products form from a single reactant.
- The breakdown of a compound into its component individual elements or other compounds falls into this reaction category.
Learn more:
Thermal decomposition brainly.com/question/11181911
#learnwithBrainly
Answer:
16
Explanation:
The proton number is always the number in the corner of the box on a periodic table
If there is an increase in industrial activity, that means that more heat will be dissipated to the atmosphere in the form of carbon dioxide. Industrialization requires fuel to keep the processes on the go. At the end of the pipeline, the combustion of fuel would result to carbon dioxide released to the atmosphere. That's how it is contributing to the global climate change through the greenhouse effect.
The question is incomplete, the complete question is
Which is NOT correct for when the silver and vanadium half-cells are connected via a salt bridge and a potentiometer? Ag^+ + 1 e^- rightarrow Ag Edegree = 0.7993 V V^2+ + 2e^- right arrow V E degree =-1.125 V Ag+ is reduced V is oxidized 1.924 V V2^+ is reduced Ag is oxidized I and II III, IV, and V I, II, and III III only IV and V
Answer:
only IV and V
Explanation:
If we look at the values of reduction potential for the two species, we will discover that vanadium has a negative reduction potential indicating its tendency towards oxidation.
On the other hand, solve has a positive reduction potential indicating a tendency towards reduction.
This implies that vanadium must be oxidized and silver reduced and not the not her way ground? Hence the answer above.