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1 year ago

Which statistic is used to determine if there is a significant difference between three or more sets of related scores

1 answer:

7 0

The t-test is a type of inference statistic used to determine if there is a significant difference between the means of two groups that may be related to a particular characteristic. The t-test is one of many tests used to test statistical hypotheses.

Inference statistics have two main purposes. Estimates for population groups (for example, the average SAT score for all 11th graders in the United States). Hypothesis testing to draw inferences about the population

One-way ANOVA is a common method for comparing three or more group means. The usual goal is to determine if the mean (or median) of at least one group is different from the other. Subsequent multiple comparison tests are often used to determine where differences occur.

Learn more about t-test here: brainly.com/question/6589776

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2 years ago

Taylor purchased 9 pints of ice cream for a party. If each guest will be served exactly 1 2 2 1 pint of ice cream, how many gu

Neporo4naja [7]

Complete question :

Carly purchased 9 1/2 pints of ice cream for a party. If each guest will be served exactly 3/5 pint of ice cream, what is the greatest number of gusts that Carly can serve

Answer:

15 guests

Step-by-step explanation:

Given that:

Total pints of icecream = 9 1/2

Fraction of ice cream pints per guest = 3/5 pints

Number of guest that can be served :

Total pints / fraction per guest

9 1/2 ÷ 3/5

19/2 * 5/3

95 / 6

= 15.8 guest

Hence, greatest Number of guest that can be served = 15

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2 years ago

In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll

maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_x\ p^x(q)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$

Hence, the probability rounded to the nearest tenth that fewer than 4 of them will say that football is their favorite sport =0.5

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2 years ago