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1 year ago

In circle A shown below the measure of angle BAD is 148 degrees If mBC is 102 degrees, what is mCD?

Mathematics

1 answer:

kati45 [8]1 year ago

6 0

The measure of arc CD from the given figure is 46 degrees

<h3>Circle theorem</h3>

From the attached figure, the expression below is true;

arcBC + arcCD = <BAD

Given the following

<BAD = 148 degrees

arcBC = 102 degrees

Substitute

arcCD =148 - arcBC

arcCD = 148 - 102

arcCD = 46 degrees

Hence the measure of arc CD from the given figure is 46 degrees

Learn more on circle theorem here; brainly.com/question/26594685

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Who can help on this for brainliest ?

k0ka [10]

Answer:

Step-by-step explanation:

$1\frac{1}{2}$ ÷ $\frac{1}{4}$ =

$\frac{3}{2} *\frac{4}{1}$ =

Hope this helps!

Pls give brainliest

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2 years ago

Read 2 more answers

Jet001 [13]

Answer:

Option D is correct.

VS = 20 units.

Step-by-step explanation:

The complete question is contained in the attached image to this answer.

From the image attached and the additional information about the triangles, it is evident that that triangle VSW is similar to triangle QSR.

Hence, we can write the ratio as

(VS/QS) = (VW/QR)

VS = 2a

QS = 2 × VS = 2 × 2a = 4a

VW = 2a - 2

QR = 3a + 6

(2a)/(4a) = (2a - 2)/(3a + 6)

Cross multiplying,

2a (3a + 6) = 4a (2a - 2)

3a + 6 = 2 (2a - 2)

3a + 6 = 4a - 4

4a - 3a = 6 + 4

a = 10

VS = 2a = 20 units.

Hope this Helps!!!

4 0

3 years ago

If two standard six-sided dice are tossed, what is the probability that a 5 is rolled on at least one of the two dice? express y

zaharov [31]

We define the probability of a particular event occurring as:
$\frac{number\ of \ desired\ outcomes}{number\ of\ possible\ outcomes}$

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.

Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:

(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5

So, we have $\frac{3}{36} = \frac{1}{12}$ probability of rolling at least one 5.