1 year ago

Let a=3/5 and let b=2/3. Compute a^2b^-3.

Mathematics

1 answer:

Amanda [17]1 year ago

7 0

Answer: 81/100

Step-by-step explanation:

I don't guarantee you I am right but..

first, solve for the exponents after substituting the numbers in

3/5 x 3/5 is 9/25

since b's exponent is negative, you change the fraction into its reciprocal and then do it with the exponent but positive

2/3^-3 to 3/2^3 and 3/2 x 3/2 is 9/4

then you mutiply both numbers to get 9/4 x 9/25 is 81/100

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