Answer: 247.67 V
Explanation:
Given
Potential At A
Potential at
when particle starts from A it reaches with velocity at Point while when it starts from C it reaches at point B with velocity
Suppose m is the mass of Particle
Change in Kinetic Energy of particle moving under the Potential From A to B
Change in Kinetic Energy of particle moving under the Potential From C to B
Divide 1 and 2 we get
on solving we get
Answer:
Electric potential energy at the negative terminal:
Explanation:
When a particle with charge travels across a potential difference
, then its change in electric potential energy is
In this problem, we know that:
The particle is an electron, so its charge is
We also know that the positive terminal is at potential
While the negative terminal is at potential
Therefore, the potential difference (final minus initial) is
So, the change in potential energy of the electron is
This means that the electron when it is at the negative terminal has of energy more than when it is at the positive terminal.
Since the potential at the positive terminal is 0, this means that the electric potential energy of the electron at the negative end is
Answer:
Velocity = 0.309 m/s
Along negative x axis
Explanation:
A pulse moving to the right along the x axis is represented by the wave function
y(x,t) = 2/ (x - 3t)² + 1
At t =0
y(x,0) = 2/ ((x - 3(0))² + 1)
=2 / (x² + 1)
At t = 1
y(x,t) = 2/ ((x - 3(1))² + 1)
= 2 /(( x - 3)² + 1)
At t = 2
y(x,t) = 2/ ((x - 3(2))² + 1)
= 2 /(( x - 6)² + 1)
For the pulse with expression y(x,t) = 4.5²
The Velocity is
V = 2.7 / 8.73
= 0.309 m/s