Yes, it can be shown as 4/15.
The answer is true I believe
Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :
t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,
The above is a quadratic equation. It can be solved by the formula as follows :
Here, a = -16, b = 32 and c = 128
Neglecting negative value, the projectile will land after 4 seconds.
AB=6 but DE=2(AB) so DE=2(6)=12
I’m guessing
Vertical stretch means the graph stretches upward, rising more rapidly than the original, the graph is steeper than the original.