Answer:
We have expanded formula of (-4x-1)² = a²+2ab+b².
So, we write the formula in square form as (a+b)².
Since we have a²-b² in step 4. We further write this as (a+b)(a-b). This is the factor formula of a²-b².
As we had two terms in place of in (a+b)(a-b), we multiply the term 'b' with '+' and '-' sign respectively.
Write the second expression given in the question.
Write the terms in the form of cube.
Write the factor formula of a³-b³) in the form of (a-b)(a²+ab+b²).
Write the H.C.F. (Highest Common Factor) of the given expressions by analysing the factors you generated in each expressions. Here, (4x²+2x+1) are the common factors.
Answer: the answer is B (0,7)
I got I right 100%
Answer:
Subtract 5, double, subtract 5 doubled, so on.
For this case we have an equation of the form:
y = A * (b) ^ t
Where,
A: initial amount
b: decrease rate
t: time in years.
Substituting values we have:
7 = A * (0.5) ^ ((1/20) * t)
For t = 45 years we have:
7 = A * (0.5) ^ ((1/20) * 45)
Clearing A:
A = 7 / ((0.5) ^ ((1/20) * 45))
A = 33.3
Answer:
the density of the substance when it was deposited 45 years ago was:
A = 33.3 milligrams per square centimeter