Answer:
0.558mole of SO₃
Explanation:
Given parameters:
Molar mass of SO₃ = 80.0632g/mol
Mass of S = 17.9g
Molar mass of S = 32.065g/mol
Number of moles of O₂ = 0.157mole
Molar mass of O₂ = 31.9988g/mol
Unknown:
Maximum amount of SO₃
Solution
We need to write the proper reaction equation.
2S + 3O₂ → 2SO₃
We should bear in mind that the extent of this reaction relies on the reactant that is in short supply i.e limiting reagent. Here the limiting reagent is the Sulfur, S. The oxygen gas would be in excess since it is readily availbale.
So we simply compare the molar relationship between sulfur and product formed to solve the problem:
First, find the number of moles of Sulfur, S:
Number of moles of S =
Number of moles of S = = 0.558mole
Now to find the maximum amount of SO₃ formed, compare the moles of reactant to the product:
2 mole of Sulfur produced 2 mole of SO₃
Therefore; 0.558mole of sulfur will produce 0.558mole of SO₃
The maximum safe operating temperature for this reaction is equal to 895°C.
<u>Given the following data:</u>
- Width of cylinder = 22 cm.
- Maximum safe pressure = 6.30mpa.
<u>Scientific data:</u>
- Ideal gas constant, R = 8.314 L-kPa/Kmol.
- Molar mass of of dinitrogen monoxide () gas = 66 g/mol.
Radius, r =
<h3>How to calculate the maximum safe operating temperature.</h3>
First of all, we would determine the volume of the stainless-steel cylinder by using this formula:
Volume, V = 10,036.81 .
In liters, we have:
Volume, V = 10.04 Liters.
Next, we would determine the number of moles of dinitrogen monoxide () gas:
Number of moles = 8.136 moles.
Now, we can solve for the maximum safe operating temperature by applying the ideal gas equation:
T = 895.02 ≈ 895°C.
Read more on temperature here: brainly.com/question/24769208
Answer:
207.89g
Explanation:
The formula of the compound is:
Fe₂S₃
Find the molar mass of the compound;
Atomic mass of Fe = 55.845g/mol
S = 32.065g/mol
Now;
Molar mass of Fe₂S₃ = 2 (55.845) + 3 (32.065)
= 207.89g
Lithium atomic number = 3
Li atom has 3 protons,3 electrons.Then it has no charge.
So the charge of Li atom here is zero.
<u>Option b: 0 is the right answer.</u>