Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
hi
I Don't know
sorry
I will try to say next time
Based on the data displayed in the histogram, the percentage of students who study 2 or more hours for the midterm is 88%.
<h3>What percentage study 2 hours or more?</h3>
First, find the number of students studying:
= 3 + 9 + 6 + 3 + 2 + 1 + 1
= 25
The number of students studying 2 or more hours for the exam are:
= 9 + 6 + 3 + 2 + 1 + 1
= 22 students
The percentage studying for two hours or more is:
= 22 / 25
= 88%
Find out more on percentages at brainly.com/question/25567167.
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