572 rounded to the nearest 10 is 570 and 572 rounded to nearest 100 is 600.
I think any of these would work
10;18
15;28
20;35
Hi! Let me help you!
- Remember, factoring looks like so:
- ab+ac=a(b+c)
- So, we need to find the greatest common factor (G.C.F.) of the polynomial.
- In this case, 6 is the GCF, so we factor it out:
- 6x²+66x+60
- Divide 6, 66 and 60 by 6:
- x²+11x+10
<u>Answer:</u>
x²+11x+10
Hope you find it helpful.
The given inequality holds for the open interval (2.97,3.03)
It is given that
f(x)=6x+7
cL=25
c=3
ε=0.18
We have,
|f(x)−L| = |6x+7−25|
= |6x−18|
= |6(x−3)|
= 6|x−3|
Now,
6|x−3| <0.18 then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03
the given inequality holds for the open interval (2.97,3.03)
For more information on inequality click on the link below:
brainly.com/question/11613554
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Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.
f(x)=6x+7,L=25,c=3,ϵ=0.18
.
The slope is calculated through the formula:
dy/dx.
If you apply this to your question you get:
(4-2)/(4-1) = 2/3 or 0.667
Hope this helps!