Ω = 2.81
A = 0.232
k = 29.8
x = A cos(ωt + Ф)
at t = 0:
x = A = A cos(ωt + Ф) = A cos(Ф)
Ф = 0
at t = 1.42, with Ф = 0:
x = A cos(ωt)
U = 1/2 k x² = 1/2 k [A cos(ωt)]²
- The net force is greatest at the position of maximum displacement
- The net force is zero when at the equilibrium position
Explanation:
The motion of a spring is a Simple Harmonic Motion, in which the displacement of the end of the spring is given by a periodic function of the form
where A is the amplitude (the maximum displacement), and the angular frequency of the motion.
We can analyze the net force acting on the spring by looking at Hooke's law:
where
F is the net force
k is the spring constant
x is the displacement
From the equation, we notice immediately that:
- The net force is the greatest when the displacement x is the greates, so at the position in which the spring has maximum compression or stretching
- The net force is zero when the displacement x is zero, so when the spring crosses the equilibrium position
Learn more about forces:
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Answer:
by using it in a such place or thing which needs it or which can work with it