Given:
The inequalities are:
To find:
The integer values that satisfy both inequalities.
Solution:
We have,
For , the possible integer values are
...(i)
For , the possible integer values are
...(ii)
The common values of x in (i) and (ii) are
Therefore, the integer values -1, 0 and 1 satisfy both inequalities.
3 consecutive integers : x, x + 1, x + 2
x + (x + 1) + (x + 2) = 108...ur equation
3x + 3 = 108...ur equation that has been simplified some
Answer:
40%
Step-by-step explanation:
(21-15)/15=0.4
0.4×100=40
Smaller number = X
Larger Number = X + 17
47 = X + (X+17)
47 = 2x + 17
47 - 17 = 2x
30 = 2x
X = 15