1. friction between water molecules
2. the wave spreads out onto a larger and larger area, so per unit area, the energy of the wave goes down
The boat traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.
Explanation:
Velocity is a physical quantity that describes the rate of change of displacement with time.
Velocity =
The quantity differs from speed in that it has both magnitude and direction.
From the options given above:
Displacement: The boat traveled in the north direction from the dock to a 200m mark.
Time taken: approximately less than 5 minutes was the duration of traveling.
This describes the boat's velocity accurately.
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Velocity
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Answer:
f1 = -3.50 m
Explanation:
For a nearsighted person an object at infinity must be made to appear to be at his far point which is 3.50 m away. The image of an object at infinity must be formed on the same side of the lens as the object.
∴ v = -3.5 m
Using mirror formula,
i/f1 = 1/v + 1/u
Where f1 = focal length of the contact lens, v = image distance = -3.5 m, u = object distance = at infinity(∞) = 1/0
∴ 1/f1 = (1/-3.5) + 1/infinity
Note that, 1/infinity = 1/(1/0) = 0/1 =0.
∴ 1/f1 = 1/(-3.5) + 0
1/f1 = 1/(-3.5)
Solving the equation by finding the inverse of both side of the equation.
∴ f1 = -3.50 m
Therefore a converging lens of focal length f1 = -3.50 m
would be needed by the person to see an object at infinity clearly
Answer:
1.73 seconds
Explanation:
The velocity the ball first hits the ground with is:
v² = v₀² + 2aΔx
v² = (0 m/s)² + 2 (-10 m/s²) (-20 m)
v = -20 m/s
The velocity it rebounds with is 3/4 of that in the opposite direction, or 15 m/s.
The time it takes to return to the ground is:
Δx = v₀ t + ½ at²
0 = (15 m/s) t + ½ (-10 m/s²) t²
0 = t (15 − 5t²)
t = √3
t ≈ 1.73 seconds
Answer:
velocity of girl with respect to surface of ice 1.154 m/s
Explanation:
Plank Mass , M = 150 kg
Girl Mass , m = 45 kg
velocity of the girl with resect to plank, v1 = 1.50 m/s
velocity of the plank + girl = v2
from the conservation of momentum
Momentum (plank+girl) = - momentum of the girl
(M+m)v2 = -mv1
v2 = -(45 kg)/(195 kg) * 1.50
v2 = -0.346 m/s
velocity of girl with respect to surface of ice =
v1+v2 = 1.50 + (-0.346) = 1.154 m/s