Answer:
<u>No, it's not a function.</u>
Step-by-step explanation:
This is not a function because the x-inputs repeat. It would be a function if each x-input was a different number, but the inputs 3 and 4 repeat twice. <u>Therefore, this is not a function.</u>
Answer:
Step-by-step explanation:
hello : write this expression
X² + y² + 6x – 2y+3 = 0 in the standard form
(x²+6x) +(y²-2y) +3 = 0
(x²+6x+9 -9) +(y²-2y+1 - 1) +3 = 0
(x²+6x+9) -9 +(y²-2y+1) - 1 +3 = 0
(x+3)²+(y-1)² = 7(the standard form)
but : 7 = (√7)²
<h2>the radius is :
√7</h2>
Answer: 6
Step-by-step explanation: why the process of elimination is because 9 is sticking like a sore thumb and the last one is too big the first one and the third one are similar but the third one has a square root of 3 so it would be THE FIRST ONE.
Answer:
V: 700
Step-by-step explanation:
refer to the pics. please rate and thumbs up
Yay, implicit differnentiation
when you take the derivitive of y, you multiply it by dy/dx
example
dy/dx y^2=2y dy/dx
for x, the dy/dx dissapears
ok
so differnetiate and solve for dy/dx
3y² dy/dx-(y+x dy/dx)=0
expand
3y² dy/dx-y-x dy/dx=0
3y² dy/dx-x dy/dx=y
dy/dx (3y²-x)=y
dy/dx=y/(3y²-x)
so at (7,2)
x=7 and y=2
dy/dx=2/(3(2)²-7)
dy/dx=2/(3(4)-7)
dy/dx=2/(12-7)
dy/dx=2/5
answer is 2/5