Answer:
D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%
Explanation:
Step 1: Detemine the mass of O in SO₂
There are 2 atoms of O in 1 molecule of SO₂. Then,
m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g
Step 2: Determine the mass of SO₂
m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g
Step 3: Detemine the mass percent of oxygen in SO₂
We will use the following expression.
m(O)/m(SO₂) × 100%
(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%
I would say diamond, because it consists only of carbon
Answer:
28.1
Explanation:
Divide the percentage abundances by 100:
92.2% ÷ 100 = 0.922
4.7% ÷ 100 = 0.047
3.1% ÷ 100 = 0.031
multiply them by their corresponding mass number:
0.922×28 = 25.816
0.047×29 = 1.363
0.031×30 = 0.93
add them all together to get your final answer:
25.816 + 1.363 + 0.93 = 28.109
to one decimal place:
28.1
I hope that helps!!!
They both are properties that form the matter which they are today!
