1) The domain is all the possible x values in the function so it would be [-4,4]
2) There are only 3 zeros shown on the graph and they are (-2, 0) (0, 0) (2, 0) the zeros are the value of x when y = 0.
3)The function is positive/Negative is asking for what x values make the y values positive aka interval notation. The function is positive if x = (0, 2) because 0 and 2 aren't included you use parentheses () instead of brackets []
The function is negative if x [-4, -2), (-2,0), (2,4]
Answer:
The given expression can't be expressed in polynomial form. Hence, it is not a polynomial.
Step-by-step explanation:
P(x,n) is a polynomial of nth degree if it is of the form,
P(x,n) =
where n is a finite positive integer and n ∈ N
and ''s are fixed but otherwise arbitrary constants ∀ i = 0(1)n .
Now, the given expression is,
which doesn't fit in the above form. Hence, it is not a polynomial.
Answer:
This is true.
Step-by-step explanation:
Step 1: see that √27 is the same as √3*3*3 and thus 3√3
Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3
Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2
if you simplify any further, you are left with 0=0, which is true.
Comment if there is any step that requires more details...