Answer:
- -25, 4, 33, 62, 91, 120, ...
Step-by-step explanation:
<h3>Given</h3>
<u>The arithmetic sequence</u>
- .. , 4, ?, ?, ?, 120, ...
<h3>To find:</h3>
<h3>Solution</h3>
<u>Let the first term a₁ = x, and common difference = d then we have:</u>
- a₁ = x
- a₂ = x + d = 4
- ...
- a₆ = x + 5d = 120
<u>The difference of the 6th and 2nd terms:</u>
- a₆ - a₂ =
- a + 5d - x - d = 120 - 4
- 4d = 116
- d = 116/4
- d = 29
<u>Then we get the first term and other missing terms:</u>
-25, 4, 4+29 = 33, 33+29 = 62, 62 + 29= 91, 91+29 = 120, ...
First, find the area of the whole square.
Area= Base times height= 48 times 96 = 4608
Next, find the area of ONE circle. The diameter is 12, so the radius would be 6
A=πr sqaured= 3.14 times 6 squared = 113.04
Next multiply by 3, since there are 3 circles.
113.04 times 3 =339.12
Subtract this value from the total area (4608)
4608-339.12=4268.88
ANSWER: 4268.88
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