The change in velocity is 2m/s
Given ,
mass of baseball m = 0.5kg
force on baseball F = 10 N
Duration .i.e. time t = 0.1s
To find here change in velocity =?
Solution,
The impulse(J) of an object is equal to,
J = F× T
Where J is the impulse of the baseball and F is force on baseball at time t.
The impulse is equal to the change in momentum of the baseball and its unit is (N.s) Newton -second. it is a vector quantity therefore the dimension is [LMT⁻¹]. Then the impulse j is given as ,
J = m(v-u)
Here J is impulse ,m is mass, (v-u) is change in velocity .From equating the both impulse equations then can be write as,
m(v-u) = F× t
(v -u) =( F × t)/m
(v -u) = (10N× 0.1 s)/0.5k
(v -u) = 2m/s
Hence the change in velocity (v -u) of baseball is 2m/s.
- A 0.5kg baseball experiences a 10n force for a duration of 0.1s. what is the change in velocity of the baseball ?
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Answer:
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Answer: 292.95 J
Explanation:
change in internal energy= Heat transfer - work done
ΔU =Q -PΔV
Here, Q = 0 as there is no heat transfer.
P =2.00 atm = 2.00 × 101235 Pa = 202470 Pa
ΔV = final volume - initial volume = 0.8 V -V = -0.2 V
where V is the initial volume.
Volume of a spherical ball, 
r = d/2 = 23.9 cm / 2 = 0.12 m
Hence, internal energy would change by 292.95 J.
