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1 year ago

If a 0.08 kg cell phone falls off a table at 15 m/s, then what is its kinetic energy right before it hits the ground?

Physics

1 answer:

Mariana [72]1 year ago

7 0

The kinetic energy of the phone right before it hits the ground is 9J.

<h3>Kinetic energy of the phone</h3>

The kinetic energy of the phone right before it hits the ground is calculated as follows;

K.E = ¹/₂mv²

where;

m is mass of the phone
v is velocity of the phone

K.E = ¹/₂(0.08)(15)²

K.E = 9 J

Thus, the kinetic energy of the phone right before it hits the ground is 9J.

Learn more about kinetic energy here: brainly.com/question/25959744

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The motion of a free falling body is an example of __________ motion

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Answer:

accelerated

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2 years ago

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3 years ago

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melisa1 [442]

answer:

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1 year ago

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Answer:

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Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

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2 years ago

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