Question

How many moles of solute are present in .75 l of a .89 m (molar) solution?

Answer 1

0.6675 moles of solute are present in .75 l of a .89 m (molar) solution.

Define the molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Given data:

V= 0.75

M=0.89

Molality = $\frac{Moles \;solute}{Volume of solution in litre}$

0.89 M=  $\frac{Moles \;solute}{0.75 L}$

Moles= 0.6675

Hence, 0.6675 moles of solute are present in .75 l of a .89 m (molar) solution.

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