Answer:
E= -3.166 cosωt V
Explanation:
Given that
I = Imax sinωt
L= 8.4 m H
Imax= 4 A
f = ω/2π = 60.0 Hz
ω = 120π rad/s
We know that self induce E given as
E= -3166.72 cosωt m V
E= -3.166 cosωt V
This is the induce emf.
The work done by the applied force on the block against the frictional force is 15.75 J.
<h3>
Work done by the applied force</h3>
The work done by the applied force is calculated as follows;
W = Fd
F - Ff = ma
where;
- F is applied force
- Ff is frictional force
Fcos(37) - μmgsin(37) = ma
Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)
0.799F - 7.077 = 0.8
F = 9.86 N
W = Fdcosθ
W = 9.86 x 2 x cos(37)
W = 15.75 J
Thus, the work done by the applied force on the block against the frictional force is 15.75 J.
Learn more about work done here: brainly.com/question/25573309
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Answer: the answer is most likely that the mirror is 120 cm tall as well
Explanation:mark brainliest PLEASE.
Answer:
14.8 m
Explanation:
S= ut + a
where u = initial velocity
S= (0 )(2) + (7.4)(2)
S= (7.4)(2)
S=14.8 m
Hey user
The energy E in joules (J) is equal to the voltage V in volts (V), times the electrical charge Q in coulombs (C):
E(J) = V(V) ×<span> Q</span>(C)
So
joule = volt × coulomb
or
J = V × C
Example
What is the energy in joules that is consumed in an electrical circuit with voltage supply of 15V and charge flow of 4 coulombs?
E = 15V × 4C = 60J