Question

How many grams of butane were in 1. 000 atm of gas at room temperature?

Answer 1

The mass in grams of butane at standard room temperature is 53.21 grams.

How can we determine the mass of an organic substance at room temperature?

The gram of an organic substance at room temperature can be determined by using the ideal gas equation which can be expressed as:

PV = nRT

• Pressure = 1.00 atm
• Volume = 22.4 L
• Rate = 0.0821 atm*L/mol*K
• Temperature = 25° C = 298 k

1 × 22.4 L = n × (0.0821 atm*L/mol*K×  298 K)

n = 22.4/24.4658 moles

n = 0.91556 moles

Recall that:

• number of moles = mass(in grams)/molar mass

mass of butane = 0.91556 moles × 58.12 g/mole

mass of butane = 53.21 grams

Learn more about calculating the mass of an organic substance here:

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