Answer:
x = 1 , y = 1 and z = 0
Step-by-step explanation:
-2x+2y+3z=0 ------(1)
-2x-y+z=-3 --------(2)
2x+3y+3z=5 ---------(3)
<u>To find the values of x,y and z</u>
(3) - (2)⇒ 2y + 4z = 2
y + 2z = 1 --------(4)
(1) - (2)⇒ 3y +2z =3 ---(5)
(5) - (4)⇒ 2y = 2
y = 1
Substituting the value of y in (4) we get z =0
Substituting the value of y and z in (1) we get x = 1
Therefore x = 1 , y = 1 and z = 0
Step-by-step explanation:
(p-3)[x²+4]+4=0
(p-3)[x²+4]=-4
(p-3)=-4/x²+4
p=-4/x²+4+3
p=-4+3(x²+4)/x²+4
p= -4+3x²+12/x²+4
p=8+3x²/x²+4
Answer:
t= 1/2
Step-by-step explanation:
hope this help
Answer:
You forgot to attach
Step-by-step explanation:
