What is the simplified form of startroot startfraction 72 x superscript 16 baseline over 50 x superscript 36 baseline endfractio

Question

1 year ago

7

n endroot? assume x ≠ 0.

1 answer:

ziro4ka [17] · Answer 1 · 2023-02-01T00:57:52+03:00

The simplified form of the given equation is $=\frac{6}{5x^{10}}$

We have given that,

$\sqrt{\frac{72x^{16}}{50x^{36} }$

Apparently, you want to simplify the given equation,

$\sqrt{\frac{72x^{16}}{50x^{36} }$

The applicable rules of exponents are,

<h3>What is the exponent rule?</h3>

(a^b)(a^c) = a^(b+c)

1/a^b = a^(-b)

(a^b)^c = a^(bc)

So the expression simplifies as

$=\sqrt{\frac{72x^{16}}{50x^{36} }}\\\\=\frac{6}{5x^{10}}$

Therefore the simplified form of the given equation is $=\frac{6}{5x^{10}}$

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