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1 year ago

The function f(t) represents the cost to connect to the Internet at an online gaming store. It is a function of t,

Mathematics

1 answer:

Maksim231197 [3]1 year ago

6 0

The statement that using an Internet connection for more than an hour and a half costs $10 is accurate. Option D is accurate.

<h3>What exactly is a function?</h3>

A function is a statement, rule, or law that specifies the connection between two variables. Functions are common in mathematics and are required for the formulation of physical connections.

The price to connect to the Internet at an online game retailer is represented by the function f(t). It is dependent on t.

The number of minutes spent online.

f(t)=$0 0 <1≤ 30

f(t)= $5 30 < t < 90

f(t)=$10 t > 90

"Any amount of time over an hour and a half would cost $10"statement is true about the Internet connection cost.

Because 90 minutes is greater than the 1 hour. If you spend greater then you have to pay the $ 10.This is shown by the third inequality.

Hence option D is correct.

To learn more about the function, refer to:

brainly.com/question/5245372

#SPJ1

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Given the following exponential function, identify whether the change

anzhelika [568]

Answer:

Growth, with a 9% increase.

Step-by-step explanation:

Exponential patterns are usually defined by some kind of repeated multiplication. In most exponential patterns we start with some initial value (let's call it a) and some multiplier (let's call it b), and a is multiplied by b some number x times. We capture this as a function y with the equation $y=ab^x$ There are three broad categories for this pattern:

No growth/decay - The function has an initial value that never changes. In order for the initial value to stay constant, we need $b=1$ , since multiplication by 1 doesn't change the number it's multiplied by.
Growth - The function grows at some exponential rate; for every increase in x, our initial value will be at least as big as it was for smaller values of x, so $b>1$ in this case. (Example: A bacteria population starts at size 3 and doubles in size every hour; after x hours, there will be $3\cdot2^x$ bacteria)
Decay - The function decays or decreases at some exponential rate; for every increase in x it can't be as large as it was for smaller values of x, so $b$ here. (Example: An Instagram post gets an initial wave of 100 new likes, and every hour it gets half the number of likes as the previous hour, so the number of new likes per hour is $100\cdot(0.5)^x$ .

In the function $y=210(1.09)^x$ , $b>1$ , so we have exponential growth, but by what percent? Well, for every step in x, we take 1.09 (109%) of the previous value, so that's a 9% increase.

4 0

2 years ago

PLEASE HELP ME ON THIS

Alex73 [517]

It's B the second one

6 0

2 years ago

Read 2 more answers

Question 9 Multiple Choice Worth 1 points) (06.01 MC) What is the value of the expression 10 - (14.48? 02 04 05 07

Step2247 [10]

Your answer is 7, hope i helped :)

6 0

2 years ago

Which fraction is equal to 15%

Andreas93 [3]

Answer:

15/100 this is the fraction for 15%

7 0

2 years ago

Find the sum of the positive integers less than 200 which are not multiples of 4 and 7

taurus [48]

Answer:

$12942$ is the sum of positive integers between $1$ (inclusive) and $199$ (inclusive) that are not multiples of $4$ and not multiples $7$ .

Step-by-step explanation:

For an arithmetic series with:

$a_1$ as the first term,
$a_n$ as the last term, and
$d$ as the common difference,

there would be $\displaystyle \left(\frac{a_n - a_1}{d} + 1\right)$ terms, where as the sum would be $\displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n)$ .

Positive integers between $1$ (inclusive) and $199$ (inclusive) include:

$1,\, 2,\, \dots,\, 199$ .

The common difference of this arithmetic series is $1$ . There would be $(199 - 1) + 1 = 199$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}$ .

Similarly, positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $4$ include:

$4,\, 8,\, \dots,\, 196$ .

The common difference of this arithmetic series is $4$ . There would be $(196 - 4) / 4 + 1 = 49$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}$

Positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $7$ include:

$7,\, 14,\, \dots,\, 196$ .

The common difference of this arithmetic series is $7$ . There would be $(196 - 7) / 7 + 1 = 28$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}$

Positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $28$ (integers that are both multiples of $4$ and multiples of $7$ ) include:

$28,\, 56,\, \dots,\, 196$ .

The common difference of this arithmetic series is $28$ . There would be $(196 - 28) / 28 + 1 = 7$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}$ .

The requested sum will be equal to:

the sum of all integers from $1$ to $199$ ,
minus the sum of all integer multiples of $4$ between $1\!$ and $199\!$ , and the sum integer multiples of $7$ between $1$ and $199$ ,
plus the sum of all integer multiples of $28$ between $1$ and $199$ - these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

$19900 - 4900 - 2842 + 784 = 12942$ .

8 0

2 years ago