All categories

1 year ago

show the step by step hybridization of hydroxonium ion H3O, draw the diagram showing the geometry and the bond angle

Chemistry

1 answer:

s344n2d4d5 [400]1 year ago

3 0

The central oxygen atom is a state of sp3 hybridization having only one available lone pair.

<h3>What is hybridization?</h3>

The term hybridization refers to the mixing of two or more atomic orbitals to yield hybrid orbitals that are suitable for bonding.

Looking at the ion H3O^+, we can see that the central oxygen atom is a state of sp3 hybridization having only one available lone pair. The image of the ion is shown here.

Learn more about hybridization in ions:brainly.com/question/16556024

#SPJ1

You might be interested in

What gives bases their properties?

svp [43]

Bases are iconic compounds that produce negative hydroxide ions (OH-) when dissolved in water. Bases taste bitter, feel slippery, and conduct electricity when dissolved in water.... Bases turn red litmus paper blue. The strength of bases is measured on the pH scale.

8 0

2 years ago

Consider a transition of the electron in the hydrogen atom from n=3 to n=7.

kow [346]

Answer:

For a: The wavelength of light is $1.005\times 10^{-6}m$

For b: The light is getting absorbed

Explanation:

For a:

To calculate the wavelength of light, we use Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $1.097\times 10^7m^{-1}$

$n_f$ = Higher energy level = 7

$n_i$ = Lower energy level = 3

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{7^2} \right )\\\\\lambda =1.005\times 10^{-6}m$

Hence, the wavelength of light is $1.005\times 10^{-6}m$

For b:

There are two ways in which electrons can transition between energy levels:

Absorption spectra: This type of spectra is seen when an electron jumps from lower energy level to higher energy level. In this process, energy is absorbed.
Emission spectra: This type of spectra is seen when an electron jumps from higher energy level to lower energy level. In this process, energy is released in the form of photons.

As, the electron jumps from lower energy level to higher energy level. The wavelength is getting absorbed.

6 0

2 years ago

Determine the correct set of coefficients to balance the chemical equation. __c6h6(l) + __o2(g)? __co2(g) + __h2o(g)

forsale [732]

To balance this equation, first we should consider balancing C because it only presents in one reactant and one product. Assuming the coefficient of C6H6 is 1, there are 6 C's in the reactant, so it generates 6CO2. Then consider balancing H for the same reason. If the coefficient of C6H6 is 1, there are 6 H's in the reactant, so it generates 3H2O.
Now that the coefficient of the products are determined, we can balance O. There are 6*2=12 O's in CO2 and 3*1=3 O's in H2O. So the total number of O in the products is 12+3 = 15. O2 is the only reactant that contains O, so to balance the equation, the coefficient of O2 should be 15/2.
Now the equation looks like:
C6H6 + 15/2O2 ⇒ 6CO2 + 3H2O.
Times both sides of the equation by 2 results the final answer:
2C6H6 + 15O2 ⇒ 12CO2 + 6H2O

3 0

2 years ago

A 2.0 M solution of LiF had 4.00 moles of LiF added to a solvent to make it.

kykrilka [37]

Answer:

2 L

Explanation:

From the question given above, the following data were obtained:

Molarity of LiF = 2 M

Mole of LiF = 4 moles

Volume =?

Molarity of a solution is simply defined as the mole per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole / Volume

With the above formula, we can obtain the volume of the solution as shown below:

Molarity of LiF = 2 M

Mole of LiF = 4 moles

Volume =?

Molarity = mole / Volume

2 = 4 / volume

Cross multiply

2 × volume = 4

Divide both side by 2

Volume = 4/2

Volume = 2 L

Therefore, the volume of the solution is 2 L.

3 0

2 years ago

10. Write the formula for the compounds: copper (1) chloride and copper (II) chloride

Natali [406]

Answer:

Copper(II) chloride (CuCl2) reacts with several metals to produce copper metal or copper(I) chloride (CuCl) with oxidation of the other metal.

Explanation:

3 0

2 years ago

show the step by step hybridization of hydroxonium ion H3O, draw the diagram showing the geometry and the bond angle​

show the step by step hybridization of hydroxonium ion H3O, draw the diagram showing the geometry and the bond angle