Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player =
The probability that athlete is a basketball player =
The probability that athlete is both basket ball player and football player =
We have to find the probability that an athlete chosen is either a football player or a basketball player .
Now we know that;
Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
Answer:
She will be 14
Step-by-step explanation:
4n=56
4*14
n=14
C
range means all possible y values
I don’t know the answer but first you need to find the perimeter for each shape that is divided by the lines. I also provide a picture above with formulas to figure out the perimeter
Px = missing length
xy = 3
Py = 6
these are the 3 sides of a right triangle; let's use the Pythagorean theorem to find Px
(Px)² + 3² = 6² subtract 3² from both sides
(Px)² = 36 - 9 simplify the right
(Px)² = 27 take the square root of both sides
Px =
Px =