Ask question

Ask question

All categories

1 year ago

8

What is the slope-intercept form equation of the line that passes through (1, 3) and (3, 7)? (1 point) y = −2x + 1 y = −2x − 1 y

= 2x + 1 y = 2x − 1

1 answer:

Stolb23 [73]1 year ago

3 0

Answer: y=2x+1

Step-by-step explanation:

The slope of the line is $\frac{7-3}{3-1}=\frac{4}{2}=2$

Using the point (1,3) to substitute into point-slope form,

$y-3=2(x-1)\\\\y-3=2x-2\\\\\boxed{y-2x+1}$

You might be interested in

Round 10,053 to the nearest hundreds?

VashaNatasha [74]

Answer:

10,100

Step-by-step explanation:

Rounding off to the Nearest hundred is giving a number which ends as 5600 or 6700 etc. To round a number to its nearest hundred you have to first look at the tenths place ( in this case 53) if a number is 50 or above you round it to the next hundred example - 5678 rounded to the nearest hundred is 5700. If a number is below 50 example - 1348, you round it to the same hundred - 1300.

Hope this helps!

6 0

1 year ago

Why is (-3,6] a better answer than (-3,6)

Pani-rosa [81]

(-3, 6) includes all numbers between -3 and 6 but it does not include -3 and 6.

when you put square parentheses you include the number on the edge

so if an anwser includes all numbers between -3 and 6 and the number 6 it's correct to write (-3,6]

7 0

1 year ago

An event manager recorded the number of people in different age groups that attended a music concert.

ehidna [41]

The third data table accurately represents data in the histogram.
If you draw the histogram, it looks like in the .jpeg image enclosed with this answer.

7 0

2 years ago

Read 2 more answers

Solve for s. 2/3 s + 5/6 s = 21 Enter the answer, as a whole number or as a fraction in simplest form, in the box.

dem82 [27]

The whole problem is in the picture. I Hope this helps

6 0

2 years ago

Read 2 more answers

Rewrite the rational exponent as a radical by extending the properties of integer exponents.

Aloiza [94]

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\\\ \textit{also recall that }a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} \qquad \qquad \sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}} \\\\ -------------------------------$

$\bf \cfrac{11^{\frac{2}{5}}}{11^{\frac{1}{4}}}\implies 11^{\frac{2}{5}}\cdot 11^{-\frac{1}{4}}\implies 11^{\frac{2}{5}-\frac{1}{4}}\implies 11^{\frac{8-5}{20}}\implies 11^{\frac{3}{20}} \\\\\\ \sqrt[20]{11^3}\implies \sqrt[20]{1331}$

5 0

2 years ago

Read 2 more answers