Answer: The plane is 6,547 feet from the closer edge of the runway.
This is a trigonometry problem that will involve setting up 2 different triangles. One going to the closer edge of the runway and the other going to the far end of the runway.
The constant between the 2 triangles is the height of the plane. You can solve for this is both triangles and set them equal to each other.
Do that will give you the equation:
x/tan(70) = (x+3000)/tan(76) where x is the distance to the closer end of the runway.
If you solve that equation, you will get x = 6547 feet.
Answer:
$14
Step-by-step explanation:
40% of 10 is 4
4+10=14
hope this helps
x = sqrt{y}k
K is the constant of proportionality.
128 = sqrt{16}k
128 = 4k
128/4 = k
32 = k
x = sqrt{y}k
x = sqrt{36}•32
x = 6 • 32
x = 192
Find y when x = 48.
x = sqrt{y}k
48 = sqrt{y}32
48/32 = sqrt{y}
(48/32)^2 = [sqrt{y}]^2
2.25 = y