Might be 1? Because it is 100 each
Hi!
This is a fun one, as it delves into basic trigonometry.
We're going to use the Pythagorean theorem here, which says that for right triangles where "c" is the hypotenuse,
a² + b² = c²
We have to split this large triangle into two parts, both of which are right triangles. (This is why they drew a line in the middle to tell you that the larger triangle is composed of two right triangles.)
Let's do the one on the right first.
We know that the length of the hypotenuse is 10, and that the length of one of the legs is 6.5. If we plug this into our equation, we'll get the length of the other leg. I'm choosing "b" to be 6.5, but it really doesn't matter if you pick "a" or "b", so long as you reserve "c" for the hypotenuse (longest side).
a² + 6.5² = 10²
a² + 42.25 = 100
a² = 57.75
√a² = √57.75
a ≈ 7.6
Therefore, the length of DC is about 7.6.
Find the length of AD using the same method (7.5 is the hypotenuse "c", and 6.5 is one of the legs "a" or "b"). Then, once you have AD, add the lengths of AD and DC to get AC.
Have a great one!
Thousands grou
the thousands group. 913,256 256 being the ones group 913 being the thousands group. the name of the period with 913, is the thousands group p
Even though we are using variables, we still know that "difference" means subtraction. So, if the larger is x1 and x2, those variables go first. The smaller, y1 and y2 will go second. So our problem will look like this:
(x1 < x2 ? x2 : x1) - (y1 < y2 ? y1 : y2)
2. measurements can be any to complementary angles.
for example, 60 & 30
3. the 2 sides are equal. Since it is an isosceles triangle.
4.an equi.triangle can never be right angled. Since, all angles are 60° in an equi.triangle.
5. right triangle can never have an obtuse angle since one angle is already 90°. therefore the other two agles are supposed to be acute angles.[ since sum of all angles in a triangle is 180°]
