Answer:
Step-by-step explanation:
The equation is x^4 – 5x^2 – 36 = 0
We will break the middle term:
Firstly multiply the coefficient of x^4 by constant term of the equation:
1*36 = 36
Now find any two numbers whose product is 36 and their sum or difference is equal to 5
9*4 = 36
9-4 = 5
Now,
x^4 – 5x^2 – 36 = 0
x^4-9x^2+4x^2-36=0
Now take the common:
x^2(x^2-9)+4(x^2-9)=0
(x^2+4)(x^2-9)=0
x²+4=0,
x²= 0-4,
x²=-4,
Take root on both sides:
√x²=+/-√-4
+/-√-4 = +/-√-1 *√4
√-1 = i
Then +/-√-1 *√4 = √4 i
We know that the root of 4 is 2
Then we can write it as +/-2i
Thus x = 2i , -2i
Now (x^2-9)= 0
x²=0+9
x²=9
Take square root on both sides:
√x²=√9
x=+/-3
x= 3, -3
Therefore the values of x are 2i, -2i, 3 , -3 ....
Answer:
Option D will be correct.
Step-by-step explanation:
The 333 erasers cost $4.41.
We have to determine the cost of 444 erasers.
Let the price of 444 erasers is $x.
Therefore, since the number of erasers cost per dollars is constant, hence the equation that would help to determine the cost of 444 erasers will be 
⇒ 
Therefore, option D will be correct. (Answer)
Answer: 2 1/3
Explanation:
10 2/6 - 7 5/6
You can make both a fraction by multiplying the denominator by the whole number, and then adding the numerator to that number, and keeping the denominator the same. So, 10*6 = 60 and 60 + 2 = 62 and you keep the denominator as 6, which would make 62/6
7*6 = 42 and 42 + 5 = 47 so 7 5/6 becomes 47/6
10 2/6 is equivalent to 62/6
7 5/6 is equivalent to 47/6
This just makes it easier to look at.
Now you just work through the equation.
62/6 - 47/6 = 15/6
15/6 = 2 3/6 = 2 1/3
Answer: 7:49
Step-by-step explanation: As you can see in the table, if you divide the number of fans present at a football game by the number of students, you would always get 7. So, 7:49 is a choice because if you divide 49 by 7, you get 7. Hope this helps!!
Answer:
2√2
Step-by-step explanation:
We can find the relationship of interest by solving the given equation for A, the mean distance.
<h3>Solve for A</h3>
<h3>Substitute values</h3>
The mean distance of planet X is found in terms of its period to be ...
The mean distance of planet Y can be found using the given relation ...
The mean distance of planet Y is increased from that of planet X by the factor ...
2√2
