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1 year ago

A rectangular sheet of paper is 12 cm long and 10 cm wide. 2 3 Find its perimeter.

Mathematics

2 answers:

jeka57 [31]1 year ago

5 0

Answer:

44 cm

Step-by-step explanation:

The paper has two sides of 12 cm = 24 cm

and two sides of 10 cm = 20 cm

total 24 + 20 = 44 cm

Aleks04 [339]1 year ago

3 0

Answer:

perimeter is 44cm

Step-by-step explanation:

We've learnt that perimeter equals the sum of all sides;

1) Make a list of your data:

Width is 10cm

Length is 12cm

2) Write the formula down and solve:

Perimeter = Length + width + length + width

P= 10+12+10+12

P=22+22

P= 44

Therefore the perimeter is 44cm

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What is the slope of the line equation 7x-3y=21

kramer

Equation: 7x - 3y = 21

3y = 7x - 21

Divide both sides by 3,

y = 7/3x - 7

Compare it with principle equation, y = mx + c

Here, slope (m) = 7/3

In short, Your Answer would be: 7/3

Hope this helps!

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2 years ago

The diagram shows a circle inside a square 16cm Work out the area of the circle

vesna_86 [32]

i can help if you have the picture

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2 years ago

Read 2 more answers

Pls tell me the answer with an explanation how you got it!

Flura [38]

Answer:

25 degrees

Step-by-step explanation:

40 + 50 = 90

2 x 25 = 5

8 0

2 years ago

Mr. Jamison deposited $100 into a new savings account on January 1. On the first day of each month thereafter, he deposited thre

Lera25 [3.4K]

Answer:

$36 400

Step-by-step explanation:

Step 1

The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.

The amount deposited in January is $\$100.$

The amount deposited in February is $1\$00\times 3= \$300.$

The amount deposited in March is $\$300\times 3= \$900.$

The amount deposited in April is $\$900\times 3= \$2\700.$

The amount deposited in May is $\$2\,700\times 3= \$8\,100.$

The amount deposited in June is $\$8\,100\times 3= \$24\,300.$

Step 2

The next step is to add up all the money that was deposited into the account. This calculation is shown below,

$\$100+\$300+900+\$\$2\,700+\$8\,100+\$24\,000=\$36\,400$

5 0

2 years ago

Read 2 more answers

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

2 years ago

A rectangular sheet of paper is 12 cm long and 10 cm wide. 2 3 Find its perimeter.​

A rectangular sheet of paper is 12 cm long and 10 cm wide. 2 3 Find its perimeter.