Answer:
South = 1.5m
West =4.2m
Explanation:
Kindly see attached a rough draft of the situation
Step one
Given data
From the sketch the direction of the player is along the resultant of the triangle, corresponding to the Hypotenuse
Step two:
Hence for an opponent to tackle him towards the south, he must be at
sin θ= opp/hyp
sin 20=x/4.5
x=sin 20*4.5
x=0.342*4.5
x= 1.5m
Also, for an opponent to tackle him towards the south, he must be at
cos θ= adj/hyp
cos 20=y/4.5
y=cos 20*4.5
y=0.93*4.5
y= 4.2m
(5 bulbs) x (25 watt/bulb) x (6 hour/day) x (30 day/month) =
(5 x 25 x 6 x 30) watt-hour/month =
22,500 watt-hour/month .
The most common unit of electrical energy used for billing purposes
is the 'kilowatt-hour' = 1,000 watt-hours .
22,500 watt-hour/month = <em>22.5 kWh/month</em>.
(22.5 kWh/month) x (1.50 Rs/kWh) = <em>33.75 Rs / month
</em>
26. D. crushing the sugar cube and dissolving it in water.
27. A. atom
28. B. molecule
29. B. plum pudding model of Joseph John Thomson
30. B. He used cathode ray tubes which showed that all atoms contain tiny negatively charged subatomic particles or electrons.
31. D. protons and neutrons are relatively heavier than electrons.
Answer:
4.157 m/s
Explanation:
Average velocity: This can be defined as the ratio change in position to time interval. The S.I unit of average velocity is m/s
The expression for average velocity is given as,
V = Δx/t.............. Equation 1
Where V = average velocity, Δx = change in position on the x- axis, t = time.
But,
Δx = x₂-x₁........... Equation 2
Substitute equation 2 into equation 1
V = (x₂-x₁)/t................ Equation 3
Given: x₂ = 32.4 m, x₁ = -5 m, t = 8.9 s
Substitute into equation 3
V = [32.4-(-5)]/8.9
V = (32.4+5)/8.9
V = 37.4/8.9
V = 4.157 m/s
Hence the average velocity = 4.157 m/s
Explanation:
This quantity is known as the specific heat capacity (or simply, the specific heat), which is the heat capacity per unit mass of a material. Experiments show that the transferred heat depends on three factors: (1) The change in temperature, (2) the mass of the system, and (3) the substance and phase of the substance.