Answer:
Let the side of one square be x. Area = x*x = x²
Then the side of other square would be 2x , Area = 2x*2x = 4x²
Combined area = x² + 4x² = 5x²
This combined area = 45 cm²
you simplify
Therefore 5x² = 45 Divide both sides by 5
x² = 45/5
x² = 9 Take square root of both sides
x = √9
x = 3
Length of larger square is 2x = 2*3 = 6 cm
Length of larger square = 6cm
Step-by-step explanation:
Answer:75
Step-by-step explanation:
Answer:
(a)18
(b)1089
(c)Sunday
Step-by-step explanation:
The problem presented is an arithmetic sequence where:
- First Sunday, a=1
- Common Difference (Every subsequent Sunday), d=7
We want to determine the number of Sundays in the 120 days before Christmas.
(a)In an arithmetic sequence:
Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.
Therefore, Aldsworth advertised 18 times.
(b)Next, we want to determine the sum of the first 18 terms of the sequence
1,8,15,...
The sum of the numbers of days published in all the advertisements is 1089.
(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.
Answer:
D = 13 units
Step-by-step explanation:
<u><em>Using Distance Formula to find the length.</em></u>
Distance Formula =
D =
D =
D =
D =
D = 13 units