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1 year ago

Which Of The Following is Graphed Below

Mathematics

1 answer:

serious [3.7K]1 year ago

4 0

Answer:

b. f(x)=1/(x-2)(x+5)

Step-by-step explanation:

this is what causes the graph to move

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Juan and his little brother Miguel ran around a circular track together. Juan ran on the inner track, which has a radius of 30 f

eduard

Answer:

80pi-60pi

Step-by-step explanation:

To find how much Juan ran, we must find the circumference.

pi *30*2=60*pi (which is how much Juan ran.)

pi*40*2=80*pi (which is how much Miguel ran)

80pi-60pi would be how much farther Miguel ran than Juan.

8 0

2 years ago

Nine squared divided by three to the fourth power

xxTIMURxx [149]

I believe it's 1. hope this helps

8 0

2 years ago

Read 2 more answers

Given (64y^2)+(4x^2)+128y+16x+64=0, transform the equation into the appropriate form

____ [38]

Answer:

(8y+8)²+(4x²+16)=0

Step-by-step explanation:

Given:

(64y²)+(4x²)+128y+16x+64=0

Find:

Equation into the appropriate form

Computation:

(64y²)+(4x²)+128y+16x+64=0

(8y)²+(2x)²+128y+16x+64=0

(8y)²+(2x)²+2(8y)(8)+2(2x)(4) + 8²=0

(8y+8)²+(4x²+16)=0

6 0

2 years ago

Which expression is equivalent to StartFraction b Superscript negative 2 Baseline Over a b Superscript negative 3 Baseline EndFr

nignag [31]

Answer:

$\frac{b^{-2}}{ab^{-3}}=\frac{b}{a}$

Step-by-step explanation:

Writing the description in algebraic translation

$\frac{b^{-2}}{ab^{-3}}$

so we have to find the expression which will be equal to $\frac{b^{-2}}{ab^{-3}}$ .

Considering the expression

$\frac{b^{-2}}{ab^{-3}}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

$\frac{b^{-2}}{b^{-3}}=b^{-2-\left(-3\right)}$

so the expression becomes

$=\frac{b^{-2-\left(-3\right)}}{a}$ ∵ $\frac{b^{-2}}{b^{-3}}=b^{-2-\left(-3\right)}$

$\mathrm{Subtract\:the\:numbers:}\:-2-\left(-3\right)=1$

$=\frac{b}{a}$

Therefore,

$\frac{b^{-2}}{ab^{-3}}=\frac{b}{a}$

7 0

2 years ago

Read 2 more answers

X:y=5:3 and x+y=56 work ouy the value of x and y

emmainna [20.7K]

Answer:

x=35, y=21

Step-by-step explanation:

A way to rewrite the first equation is $\frac{x}{y} =\frac{5}{3}$

after cross-multiplying, we get 3x=5y.

If we solve for one variable, we can substitute it into the other equation.

Let's solve for x.

3x=5y

x=(5/3)y

Now, we can substitute x=(5/3)y in the equation x+y=56.

(5/3)y+y=56

(8/3)y=56

y=21

Going back to x+y=56, we can now plug back in y, knowing that it is 21.

x+21=56

x=35.

8 0

2 years ago