Answer:the answer is a
Explanation:I’m 90% positive.
Answer:
heptan-3-one and heptan-2-one
Explanation:
In this case, we must remember what the products of this reaction are. An alkyne in the presence of HgSO4 and H2SO4 will produce a ketone. But, in the triple bond, we have two carbons, therefore the carbonyl group can be placed on any of the carbons of the triple bond.
In figure 1 we have the general reaction. At C = O it can be added to the carbon on the left (red carbon) or the carbon on the right (blue carbon).
Following this logic, for 2-heptyne the carbonyl group can be added to carbon 2 producing <u>heptan-2-one</u>. Similarly, the carbonyl group can be added to carbon 3 producing <u>heptan-3-one</u>. (See figure 2)
Answer:
The strong acid reacts with the weak base in the buffer to form a weak acid, which produces few H+ ions in solution and therefore only a little change in pH.
Explanation:
When a strong acid is added to the buffer, the acid dissociates and furnish hydrogen ions which combine with the conjugate of the weak acid, forming weak acid. The weak acid dissociates to only some extent and can furnish only some protons and there is no significant change in the pH.
Hence, option B is correct.
Answer:
12430mL of water must be added
Explanation:
To solve this question we need to convert the 20%w of CuSO₄ to molarity. Then, using the <em>diulution factor </em>we can find the amount of water required:
20g CuSO₄ / 100mL * (1mol / 159.609g CuSO₄) = 0.1253 moles / 100mL = 0.1253mol / 0.1L =
1.25M is the concentration of CuSO₄. To dilute this concentration to 0.01M, the dilution factor must be of:
1.25M / 0.01M = 125 times must be diluted the solution.
As the volume of the concentrated solution is 100mL, the total volume of the solution to have a 0.01M solution must be of:
100mL * 125 times = 12530mL is the final volume of the solution. That means the amount of water added must be of:
12530mL - 100mL =
<h3>12430mL of water must be added</h3>