To solve for the confidence interval for the population
mean mu, we can use the formula:
Confidence interval = x ± z * s / sqrt (n)
where x is the sample mean, s is the standard deviation,
and n is the sample size
At 95% confidence level, the value of z is equivalent to:
z = 1.96
Therefore substituting the given values into the
equation:
Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)
Confidence interval = 3 ± 1.59
Confidence interval = 1.41, 4.59
Therefore the population mean mu has an approximate range
or confidence interval from 1.41 kg to 4.59 kg.
Answer:
16.9265381881
Step-by-step explanation:
Tangent = Opposite/Adjacent.
Thus, tan62 = x/9 --> tan62 = 1.88072646535, multiply by 9 to get x, 1.88072646535* 9 = 16.9265381881
Answer:
The most tickets were written on Saturday .On Saturday 325 tickets were issued
Step-by-step explanation:
The average number of traffic tickets issued in a city on any given day Sunday-Saturday can be approximated by
Where x represents the number of days after Sunday
T(x) represents the number of traffic tickets issued.
Sunday = x=0
Monday = x=1
Tuesday = x=2
Wednesday = x=3
Thursday = x =4
Friday = x=5
Saturday = x=6
Substitute x= 0
On Sunday 37 tickets were issued
Substitute x= 1
On Monday 115 tickets were issued
Substitute x= 2
On Tuesday 181 tickets were issued
Substitute x= 3
On Wednesday 235 tickets were issued
Substitute x= 4
On Thursday 277 tickets were issued
Substitute x= 5
On Friday 307 tickets were issued
Substitute x= 6
On Saturday 325 tickets were issued
Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued
16x = 45 - 29
16x = 16
x = 16/16
x = 1