Let AM be the distance between point A and the right wall and AN be the distance between A and the left wall.
Δ AMB is an isosceles right triangle and Δ ANC is half of an equilateral triangle.
Length of AM = 30 m. Length of AN = 1/2 · 80 = 40 m.
The distance between the walls is:
30 m + 40 m = 70 m.
1/2 * 2/3 *3/4 * ... * 1999/2000
Observe, every numerator cancels with denominator
that leaves 1/2000
Answer:
the answer would be d., have a good day
<h3>
Answer: 4</h3>
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Explanation:
For now, ignore the variables. Let's just focus on the coefficients 12 and 16.
The GCF of 12 and 16 is 4 because this is the largest factor they have in common.
12 = 4*3
16 = 4*4
You could create a factor tree to get the prime factorization of each number
12 = 2*2*3
16 = 2*2*2*2
Each factor tree has two copies of '2' leading to the GCF 2*2 = 4.
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Now let's go back to the variables. The term 12n and 16w^3 do not have any variables in common. So the final answer won't have any variables in it. If both terms had say a 'w' in them, then w would somehow be involved in the GCF. But that's not the case here. So we just stick to 4 as our answer.
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Side note: If you had 12n+16w^3 and you wanted to factor, then you would factor out the GCF 4 to get 12n+16w^3 = 4(3n+4w^3). Use the distribution rule to confirm this.
Answer:
Therefore 164 children and 89 adults swam at the public pool that day.
Step-by-step explanation:
Given that,
253 people used the public swimming pool.
The daily prices for children are $1.50 and for adults are $2.25.
Let the number of children be x.
Then number of adult is (253-x)
The total money collect on that day is
According to the problem,
Therefore 164 children and (253-164)=89 adults swam at the public pool that day.