Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
On order to change B to C, you have to bring B 3 units to the right and then 4 units down.
Answer:
This is a line, x>0 (miles cannot be negative)
Step-by-step explanation:
Cost of renting a car = cost per mile times the number of miles plus the flat fee
We know the cost per mile = .25 and the flat fee
Let x = number of miles and y = cost of renting a car
y = .25x+15
This is in the form y= mx+b which is the slope intercept form of a line.
1 to 3
Since you know that he landed on tails 8 out of 32 times, he must have flipped heads for the flips he did not flip tails. So, subtract 32 minus 8, which equals 24, and your answer is 8 to 24. Simplify this like you would with a fraction; the greatest common factor is 8 so divide the "numerator" and the "denominator" by 8. Therefore your final answer is 1 to 3.
