For this case we have the following equation:
Where, we have the following variables:
x: time in seconds
y: speed in feet per seconds
For the initial velocity, we evaluate x = 0 in the given equation:
Therefore, the initial speed is 12 feet per second.
Answer:
The particle's initially velocity is 12.
Hello, hehelol12.
The length of PR is the same as TR.
Length of PR = 11.
The measure of angle PQR is the same as angle RST.
Measure of angle PQR = 39
I hope this helps you out!
PS. Brainliest would be appreciated. :)
Answer:
<em>The answer for the first question is: </em>
<em>12/80 =</em>
<em>12 ÷ 80 =</em>
<em>0.15 =</em>
<em>0.15 × 100/100 =</em>
<em>0.15 × 100% =</em>
<em>(0.15 × 100)% =</em>
<h2><em>
15%</em></h2>
<em>Then, the answer for the second question is: </em>
<em>75% × 52 =</em>
<em>(75 ÷ 100) × 52 =</em>
<em>(75 × 52) ÷ 100 =</em>
<em>3,900 ÷ 100 =</em>
<h2><em>
39 </em></h2>
* Hopefully this helps:) Mark me the brainliest:)!!!
Answer:
0.066
Step-by-step explanation:
We solve this question using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation
For the question
mean birth weight for boys is 3.27 kg, with a standard deviation of 0.51 kg.
x = 2.5
Hence:
z = 2.5 - 3.27/0.51
z = -1.5098
Probability value from Z-Table:
P(x ≤ 2.5) =P(x < 2.5) = P(x = 2.5) =
=0.065547
Therefore, the proportion of baby boys that are born with a low birth weight is 0.066
1) y= - 2x² + 8x. It's a parabola open downward (a<0)
2) x - 2.23.y + 10.34 = 0 . Re-write it : y = (x/2.23) + (10.34/2.23), a linear equation.
To find the intersections between 1) & 2), let 1) = 2)
-2x² + 8x = (x/2.23) + (10.34/2.23)
-2x² + 8x - (x/2.23) - (10.34/2.23) =0 ; solve this quadratic for x values:
x' (that is A) = 0.772 & x" (that is B) = 3. (these are the values of x-intercept (parabola with line). To calculate the y-values, plug x' & x' in the equation:
for x' = 0.772, y = 0.34 → B(0.772 , 0.34)
for x" = 3, y = 0.016 → A(3 , 0.O16)
So B IS AT 0.34 Unit from the ground
