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1 year ago

6

The length of a rectangular poster is 2 more inches than three times its width. The area of the poster is 33 square inches. Solv

e for the dimensions (length and width) of the poster.
If you give a troll answer, i will report

1 answer:

laiz [17]1 year ago

7 0

Answer:

Step-by-step explanation:

Area of the rectangle = 33 inches sq

Area of a rectangle (formula) = l*b

let the width be x

length = 2 inches + 3x = 2+3x

Area of the rectangle = l*b = 2+3x + x

33 inches sq = 2+3x + x

33 in sq = 2+4x

33/2 = 4x

16.5/4 = x

x = 4.125

width= <u>4.125 inches</u>

length = 2+3x = 2+3(4.125) = <u>14.375</u>

<u></u>

(unless your poster is 32 sq inches and you made a mistake, just replace 33 with 32 and solve it)

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tankabanditka [31]

The number of candies that will be <u>left over</u> after giving everyone an equal amount is equal to 23.

<u>Given the following data:</u>

Total number of candy = 320 pieces

Number of classmates = 27 classmates

To calculate the number of candies that will be <u>left over</u> after giving everyone an equal amount:

In this exercise, you're required to determine the number of candies Phillipe would have as <u>left over</u> after giving everyone in his class an equal amount of candies.

<h3>How to solve this word problem.</h3>

Thus, we would find the number of times 27 would divide 320 without any remainder.

$\frac{320}{27} = 11 \frac{23}{27}$

From the mixed fraction, we can deduce that the remainder is 23.

Therefore, the number of candies that will be <u>left over</u> after giving everyone an equal amount is equal to 23.

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4 0

1 year ago

Help! You can look at the picture please

viva [34]

Answer:

$\frac{3x}{3 - 2x}$

Step-by-step explanation:

Here,

f(x) = y

$y = \frac{3x}{2x + 3}$

or , swapping x with y

$x = \frac{3y}{2y + 3}$

now to solve for y we get

$y = \frac{3x}{3 - 2x}$

now we put f inverse x instead of y

${f}^{ - 1} (x) = \frac{3x}{3 - 2x}$

I am done.

4 0

3 years ago

Read 2 more answers

Hi, Could anyone help me with my homework

tatiyna

Answer:

$\hookrightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

solving steps:

$\rightarrow \sf (x + 4)^6$

$\bold{rewrite \ the \ following}$

$\rightarrow \sf (x + 4)^2 (x + 4)^2 (x + 4)^2$

$\bold {formula \ used : \sf (x+a)^2 = (x^2 + 2xa + a^2)}$

$\rightarrow \sf (x^2 + 8x+16) (x^2 + 8x+16) (x^2 + 8x+16)$

$\bold{simplify \ by \ removing \ parenthesis}$

$\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)$

$\bold{basic \ addition \ of \ integers }$

$\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)$

$\bold{remove \ parenthesis}$

$\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)$

$\bold {final \ answer:}$

$\rightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

8 0

1 year ago

What is the recursive rule for the sequence?

adoni [48]

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5 0

2 years ago

Pls help, u dont have to explain that much

Anettt [7]

Answer:

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$12x {}^{3}$

okay....

Step-by-step explanation:

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( where l = length, b = width , h = height )

so volume of given cuboid = ( 3x × 2x × 2x )

hence volume =

${12x}^{3}$

5 0

2 years ago