Question

Determine the empirical formula for a compound that is 64.8% C, 13.6% H, and 21.6% O by mass.

Answer 1

Answer:

C4H10O

In case it's not understandable: c four, h ten, no

Explanation:

Molar mass of each component: C = 12.0107, H = 1.00794, O = 15.9994

Convert to moles: C = 5.3951892895502, H = 13.492866638887, O=1.3500506268985

Find the smallest mole value: 1.3500506268985

Divide all components by the smallest value: C = 3.9962866444087, H=9.9943412269543, O = 1

Round to closest whole numbers: C = 4, H = 10, O = 1

Combine to get the empirical formula: C4H10O