A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC.
There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be:
3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways
Answer:
look up desmos graphing calculator! you're welcome x
Step-by-step explanation:
Answer:
p*106.5/100
Step-by-step explanation:
C.√93
A=17
B=14
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