A pressure gauge at elevation 12m at the side of a tank containing a liquid reads 80 kpa. Another gauge at elevation 7m reads 12

Question

1 year ago

6

0 kpa. Compute the specific gravity of the liquid?

1 answer:

Vlad1618 [11] · Answer 1 · 2023-04-01T04:10:05+03:00

The specific gravity of the liquid is 8 kN/m³.

<h3>What is specific gravity?</h3>

The specific gravity is given as the ratio of the density of the substance with respect to the reference material.

The specific gravity with liquids at varying pressure is given with the Bernoulli's equation as:

$\rm \dfrac{P_1}{\gamma} \;+\;z_1 \;=\;\dfrac{P_2}{\gamma}\;+\;z_2$

Substituting the pressure (P), the elevation (z), the specific gravity (γ) is given as:

$\rm \dfrac{P_1}{\gamma}-\dfrac{P_2}{\gamma}=z_2-z_1\\\\\gamma =\dfrac{P_1-P_2}{z_2-z_1}\\\\\gamma=\dfrac{120-80\;kpa}{12-7\;m}\\\\\gamma=8kN/m^3$

Thus, the specific gravity of the liquid is 8 kN/m³.

Learn more about specific gravity, here:

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