The answer is (3) 3. The calculation rule of significant figures is when multiplication and division, the significant figures of result is equal to the least of the numbers involved. The significant figure of 2.70 and 80.01 is 3 and 4.
Answer:
312 g of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Next, we shall determine the number of mole of O₂ produced by the reaction of 6.5 moles of KClO₃. This can be obtained as follow:
From the balanced equation above,
2 mole of KClO₃ decomposed to 3 moles of O₂.
Therefore, 6.5 moles of KClO₃ will decompose to produce = (6.5 × 3)/2 = 9.75 moles of O₂.
Finally, we shall determine the mass of 9.75 moles of O₂. This can be obtained as follow:
Mole of O₂ = 9.75 moles
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ =?
Mole = mass / Molar mass
9.75 = Mass of O₂ / 32
Cross multiply
Mass of O₂ = 9.75 × 32
Mass of O₂ = 312 g
Thus, 312 g of O₂ were obtained from the reaction.
<span>The root mean square speed is given by V_rms = âšRT/M where r, t, and m are the rate constant, temperature and molar mass the gas
Average molar kinetic energy of the gas
E = 1/2 M * (V_rms)^2 = 8750 ms/1
So (V_rms)^2 = (2 * 8750) / M
Molar mass of 2 chlorine atoms in kg is 2 * 35 * 10^(-3)
Hence we have (V_rms)^2 = (2 * 8750)/ (2 * 35 * 10^(-3))
(V_rms)^2 = 8750/0.035 = 250000
So V_rms = âš 250000 = 500</span>
D) 500 meters
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<h2>Answer:</h2>
Moles of a gas = 0.500
Volume = 2.50 L
Pressure = 13. atm
Temperature = ?
Solution:
Formula:
PV = n RT
Putting the values in formula:
T = PV/nR = 13 * 2.5 / 0.5 * 0.082057
= 32.5/0.041 = 792.68 K
T = 792.68 K