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1 year ago

Select two ratios that are equivalent to 4:18.

Mathematics

1 answer:

dedylja [7]1 year ago

7 0

Answer: The two ratios that are equivalent to 4:18 include 2:9 and 8:36

Step-by-step explanation:

To be able to solve this question, we've to simplify the given ratio. Therefore, 4:18 will be reduced to the lowest term and this will be:

= 4/18 = 2/9

Also, when 4/18 is multiplied by 2 for both the numerator and denominator, the value will be:

= 4×2/18×2

= 8/36

Therefore, the correct options will be B(2:9) and E(8:36).

it is easy.....

first, convert this ratio into a fraction

4 : 18 = 4/18

now , equivalent fractions

= 4 = 4 × 2 , 4 × 3

18 = 18 × 2 ,18 × 3

now answer

= 4/18 , 8/36 , 12/54

again covert into ratio

= 4:18 , 8:36 , 12:54

36 and 2 are (the GCF and the LCM)

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

Find the prime factors of each term to find the greatest common factor (GCF).

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HELP I RLLY NEED IT

Free_Kalibri [48]

Answer:

$\Large \textnormal{(A). Always}$

Step-by-step explanation:

A square is always a parallelogram. I hope this helps!

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2 years ago

Help me please!!! I am so thankful for those who will help me

Novosadov [1.4K]

ASA stand for Angle-Side-Angle. So, if you were using this theorem to prove congruence, you would need two triangles where you know two of the angles, and the side in between the two angles.

The triangles in answer C) match that description, so C is your answer.

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2 years ago

What fraction is equal to 0.272727.....

Serhud [2]

The fraction at its simplest form is 3/11

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2 years ago

onji has $5.25 in nickels and dimes.The coin value can be modeled by the equation 0.10d + 0.05n = 5.25, where d represents the n

Maru [420]

This is how you solve this problem:
.10d + .05n = 5.25

(plug in the number of dimes we have)

(21 x .1) + .05n = 5.25

(multiply number of dimes x value of the dime)

2.10 + .05n = 5.25

(subtract 2.10 from both sides)

.05n = 3.15

(divide both sides by .05 to get the number of nickels)

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Hope this helps!

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2 years ago

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

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2 years ago